The PWI 500 was released on Thursday, and AEW World Champion Jon Moxley has been ranked number one.
Jon replaces his ex-Shield team-mate Seth Rollins who finished first last year.
The evaluation period for the ranking is July 1, 2019 to June 30, 2020 and the criteria is as follows:
Win-loss record, technical ability, influence in the sport, success against the highest grade of competition, success against the most diverse competition and activity.
During this period, Moxley competed in the NJPW G1 Climax in July, with the highlight of his campaign being an epic brawl against Tomohiro Ishii.
In the autumn he turned his attention back to AEW and defeated Kenny Omega in a brutal ‘Lights Out’ match in the main event of AEW Full Gear, a match which drew considerable attention for its gore and violence.
Moxley then entered into a feud with AEW World Champion Chris Jericho and in the Inner Circle before capturing the World Championship from Jericho in the main event of AEW Revolution in February 2020.
This victory meant Moxley became the first person to hold both the AEW World Championship and the NJPW IWGP US Championship simultaneously after he recaptured the latter from Lance Archer at Wrestle Kingdom 14.
Since then Moxley has successfully defended the AEW Championship against Jake Hager, Brodie Lee, Brian Cage and Darby Allin.
The award tops off a fantastic year for Moxley.
He revealed in interviews that left WWE because he did not enjoy working there, despite being offered substantial amounts to stay. He has won gold in two promotions and is now ranked the number one wrestler in the world by PWI.
The official top 10 list is as follows
- 1. Jon Moxley
- 2. Adam Cole
- 3. Chris Jericho
- 4. Drew McIntyre
- 5. Tetsuya Naito
- 6. Kazuchika Okada
- 7. Cody Rhodes
- 8. Seth Rollins
- 9. Kofi Kingston
- 10. AJ Styles
If you would like to read the full PWI issue and list, it can be purchased here: